Friday, November 7, 2008

BIIF Mathematics, er, Division Championship Implications

You might as well give the first person to solve this BIIF Football Division 2 mathematical equation a state title.

Oh wait, that would be me.

On behalf of my iPhone's Calculator, newspaper archives and radio highlights, and my smart brain, I would humbly accept this prestigeous award of BIIF Football Mathematician of the Year.

Okay, all kidding aside, thats pretty much what it takes to figure out all of the tiebreakers for a possible Kamehameha win. You ready?

If Kamehameha beats Konawaena by 7 points or less, the Konawaena Wildcats are DII Overall Champions

If Kamehameha beats Konawaena by 8 points, it creates a 2nd tie between HPA and Konawaena

If Kamehameha beats Konawaena by 9-10 points, HPA is the 2nd round champion and would play Konawaena next week

If Kamehameha beats Konawaena by 11 points, it creates a 2nd tie between HPA and Kamehameha

If Kamehameha beats Konawaena by 12 points or more, Kamahemeha is the 2nd round champion and would play Kona next Friday.

Of course all of this means nothing if one thing happens:

KONAWAENA WINS

Good luck.

You can hear this matchup on Saturday beginning at 7 pm on ESPN Radio.

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